If x+4 is a factor of x^2-ax-12a and a is a constant, what is the value of a?

asked Nov 14, 2023 35.8k views

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by Fred

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Answer:

$x^(2) -ax-12a=(x+4)(x-4-a)-8a+16\\x+4 is a factor of x^2-ax-12a\\-8a+16=0\\a=2$

Step-by-step explanation:

Bensal answered Nov 20, 2023

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