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2a+3r+1.5p=29.75 (1) a+r+p=13.50 (2) a+3r+4p=29.00 (3) Eliminate a by multiplying equation (2) by -1 and adding it to equation (3). What is the resulting equation? 4r + 5p = 42.…

2a+3r+1.5p=29.75 (1) a+r+p=13.50 (2) a+3r+4p=29.00 (3) Eliminate a by multiplying equation (2) by -1 and adding it to equation (3). What is the resulting equation? 4r + 5p = 42.…
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2a+3r+1.5p=29.75 (1)

a+r+p=13.50 (2)

a+3r+4p=29.00 (3)

Eliminate a by multiplying equation (2) by -1 and adding it to equation (3).

What is the resulting equation?

4r + 5p = 42.50

2r + 3p = 15.50

2r + 3p = 42.50

asked
User Wakil Ahmed
by
7.7k points

1 Answer

1 vote

Answer:

2r+3p=15.50

Explanation:

answered
User Manzapanza
by
7.9k points
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