Question

The width of a certain rectangle is 2 m greater than half its length. Four times its length is 26 m greater than its perimeter. What are the dimensions of the rectangle?

Answer 1

Length = 30

Width = 17

Explanation:

Let L = length of rectangle and W = Width

The first sentence gives the equation

W = L/2 + 2 ==>

2W = L +4 ==>

L = 2W - 4 .... (1)

The perimeter of the rectangle is 2(L+W) = 2L +2W

Second sentence gives us the equation

4L = 2L + 2W + 26 ===>
2L = 2W + 26 ...... (2)

(2) - (1) ==> L = 30 (2W cancels out)

From (1), W = 30/2 + 2 = 15 + 2 = 17

Check:
Using these values and substituting in equation 2 gives us
2 * 30 = 2* 17 + 26
60 = 34 + 26
which matches