Question

Find the x- and y-intercepts of the parabola y=x2+10x+4

Answer 1

x-intercepts: -5 +/-
`√(21)`. y-intercept: 4

Explanation:

For x-intercepts use the quadratic equation

`x= (-b +/-√(b^2-4ac) )/2a`

Fill in your values:

`x= (-10 +/-√(100-16) )/2`

And solve

`x=-5 +/- √(21)`

For y-intercepts set x=0 and solve. In this case, setting x= 0 gives you y=4.