Determine the inductance of a solenoid with 650 turns in a length of 28 cm . The circular cross section of the solenoid has a radius of 3.5 cm .

Question

asked Aug 20, 2021 205k views

1 Answer

VHanded · Answer 1 · 2021-08-24T05:28:19+0000

Answer:

The value is
$L = 0.0073 \ H$

Step-by-step explanation:

From the question we are told that

The number of turns is
$N = 650 \ turns$

The length is
$l = 28 \ cm = 0.28 \ m$

The radius of the cross-section is
$r = 3.5 \ cm = 0.035 \ m$

Generally the cross-sectional area is mathematically represented as

$A = \pi * r^2$

=>
A = 3.142 * 0.035^2

=>
$A = 0.00384 \ m^2$

Generally the inductance is mathematically represented as

$L = (N^2 * \mu _o * A )/( l)$

Here
$\mu_o$ is the permeability of free space with value
$\mu_o = 4\pi * 10^(-7) N/A^2$

=>
$L = ( 650^2 * 4\pi * 10^(-7) * 0.00384 )/(0.28)$

=>
$L = 0.0073 \ H$