Question

CAN SOMEONE PLEAEE HELP ????!!!!!! I will mark Brianliest !!!!!!!!!!!!!!!!!!

Answer 1

I don't know if I'm correct but the answer is 6.

Explanation:

I'm not 100% correct, but you set the other two angles to add to each other then set it equal to angle QRS and i got x=6.

Your equation should be like this: 3x + 17 + 2x +21 = 10x -1

than you solve form there

I;m not sure that this is the correct answer and maybe i'm wrong, but hope this helps

Answer 2

59°

Explanation:

According to the given description,
`\angle QRS` is the exterior angle of
`\triangle PQR`

So, by exterior angle property of a triangle, we have:

`m\angle QRS=m\angle RPQ+m\angle PQR\\\\</p><p>(10x - 1)\degree = (3x +17)\degree+(2x +12)\degree\\\\</p><p>(10x - 1)\degree = (3x +17+2x +12)\degree\\\\</p><p></p><p>(10x - 1)\degree = (5x +29)\degree\\\\</p><p></p><p>(10x - 1)= (5x +29)\\\\</p><p></p><p>10x - 5x = 29 + 1\\\\</p><p>5x = 30\\\\</p><p>x = (30)/(5)\\\\</p><p>x = 6\\\\</p><p></p><p>\because m\angle QRS = (10x - 1)\degree \\\\</p><p></p><p>\therefore m\angle QRS = (10* 6- 1)\degree \\\\</p><p>\therefore m\angle QRS = (60- 1)\degree \\\\</p><p>\huge\orange{\boxed{\therefore m\angle QRS = 59\degree }}\\</p><p>`