Question

How would I solve this

Solve the quadratic equation 3x^2+x-5=0

Give your answers to 2 decimal places.

Answer 1

x = -1/6 + 1/6√61 or x = -1/6 + -1/6 √61

Explanation:

3x^2+x-5=0

Using quadratic formula a=3, b=1, c=-5

x = -b ± √b^2 - 4ac / 2a

x = -(1) ± √(1)^2 - 4(3)(-5) / 2(3)

x = -1 ± √61 / 6

x = -1/6 + 1/6√61 or x = -1/6 + -1/6 √61

Answer 2

x= 1.13 or x= -1.45

Explanation:

use the quadratic square root formula (-b±√(b²-4ac))/(2a) .

a= 3

b=1

c= -5

replace the variables with the numbers listed above and just work out.

x= 1.13 or x= -1.45