Question

Which point lies on the circle x^2+y^2=100
A (0,-100)
B (10,-10)
C (25,75)

Answer 1

NOT a single ordered pair satisfies the equation.

Explanation:

Given the equation

`x^2+y^2=100`

Let us substitute all the given ordered pairs to find which ordered pair satisfies the equation.

For (0, -100)

`x^2+y^2=100`

substitute x=0 and y=-100

`0^2+\left(-100\right)^2=100`

`10000=100`

FALSE

Thus, the ordered pair (0, -100) does NOT satisfy the equation.

For (10, -10)

`x^2+y^2=100`

substitute x=10 and y=-10

`10^2+\left(-10\right)^2=100`

`200=100`

FALSE

Thus, the ordered pair (10, -10) does NOT satisfy the equation.

For (25, 75)

`x^2+y^2=100`

substitute x=25 and y=75

`25^2+\left(75\right)^2=100`

`6250=100`

FALSE

Thus, the ordered pair (25, 75) does NOT satisfy the equation.

Therefore, NOT a single ordered pair satisfies the equation.