asked 105k views
2 votes
How many milliliters of a stock solution of 6.20 M HNO3 would you have to use to prepare 0.130 L of 0.470 M HNO3?

1 Answer

3 votes

Answer:

9.85

Step-by-step explanation:

M1V1 =M2V2

6.20×v1= 0.470×0.130

v1 = ( 0.470 × 0.130 ) ÷ 6.20

v1 = 0.0098 L × 1000

V1 = 9.8 ml

answered
User Dgeorgiev
by
8.2k points

No related questions found