Question

454 grams of isomaltitol, C12H24O11, was combusted in a furnace completely in an excess oxygen. The products of this reaction are water and carbon dioxide. What is the theoretical yield (in kilograms) of water produced from this reaction?

Answer 1

The theoretical yield (in kilograms) of water produced from this reaction : 0.285 kg

Further explanation

Reaction

2C₁₂H₂₄O₁₁ + 25O₂ → 24CO₂ + 24H₂O

mass of C₁₂H₂₄O₁₁ - isomaltitol = 454 g

mol C₁₂H₂₄O₁₁(MW=344.31 g/mol) :

`\tt mol=(mass)/(MW)\\\\mol=(454)/(344.31 g/mol)\\\\mol=1.319`

mol H₂O based on C₁₂H₂₄O₁₁ as limiting reactant(O₂-oxygen as an excess)

From the equation above, mol ratio of C₁₂H₂₄O₁₁ : H₂O = 2 : 24, so mol H₂O:

`\tt mol~H_2O=(24)/(2)* 1.319=15.828`

then mass H₂O (MW=18 g/mol) :

`\tt mass=mol* MW\\\\mass=15.828* 18=284.904~g=0.285~kg`