Question

Find the solution of the system of equations.
8x + 6y = 28
9x + 3y = 39

Answer 1

8x + 6y = 28
9x + 3y = 39

to first solve the system, we need to isolate one variable. we will solve for x first so we need to cancel out the y. to do this, we will multiply the second equation by -3

8x + 6y = 28
(9x + 3y = 39) -2

8x + 6y = 28
-18x -6y = -78

now combine

-10x = -50

divide by -10

x=5

now we plug x back into the equation to solve for y

8(5)+6y = 28

40 + 6y = 28

6y= -12

y= -2