Question

Find the slope of the line that contains (10,-1) and (-8,6)

Answer 1

the slope of the line that passes throught (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)

given

(-4,3) and (-8,6)

slop=(6-3)/(-8-(-4))=(3)/(-8+4)=3/-4=-3/4

slope is -3/4

Explanation:

Answer 2

(y2-y1)/(x2-x1)

(6+1)/ (-8-10)

7/ -18 is the slope

Explanation: