Question

How many moles of Ba(NO3)2 are there in 0.25 L of a 2.00 M Ba(NO3)2 solution?

Use Molarity equals StartFraction moles of solute over liters of solution EndFraction..
0.13 mol
0.50 mol
2.25 mol
8.0 mol

Answer 1

b

Step-by-step explanation:

got it right on test

Answer 2

0.5moles

Step-by-step explanation:

Given parameters:

Volume of solution= 0.25L

Molarity of solution = 2.00M

Unknown:

Number of moles = ?

Solution:

To solve this problem;

Molarity is the number of moles of solute in a given volume of solution, so

Number of moles = molarity x volume

Now insert the parameters and solve;

Number of moles = 0.25 x 2 = 0.5moles