Question

N2 + 3H2, -> 2NH3

If I have 50.6 L of N2 and excess H2, how many liters of NH3 can I produce?

Answer 1

C. 101.2 L

Step-by-step explanation:

N2 + H2= NH3

Balancing it,

N2 + 3 H2 = 2.NH3

(1 mol) (3 mol) (2 mol)

which means

1 molecule of nitrogen reacts with 3 molecule of hydrogen to form ammonia.

Likewise,

50.6 l of nitrogen reacts with 50.6 × 3= 151.8 l of hydrogrn to form 50.6 × 2= 101.2 l of ammonia.