Question

What the trinomial factor of this problem

Answer 1

`x^2-9x+20=(x-4)(x-5)`

Explanation:

Factoring a Trinomial

A second-degree trinomial can be expressed as:

`ax^2+bx+c`

It can be factored, i.e., converted to a product instead of a sum of terms in several ways.

We'll use the grouping method.

Factor:

`x^2-9x+20`

Split the second term into two terms:

`x^2-4x-5x+20`

Factor x on the first two terms and -5 on the last two terms:

`x(x-4)-5(x-4)`

Now factor out x-4:

`(x-4)(x-5)`

Thus:

`\mathbf{x^2-9x+20=(x-4)(x-5)}`