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What is the equation of a line perpendicular to y-2=-2/3(x+1) and passing through the point (4,1) PLS HELP

What is the equation of a line perpendicular to y-2=-2/3(x+1) and passing through the point (4,1) PLS HELP
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What is the equation of a line perpendicular to y-2=-2/3(x+1) and passing through the point (4,1)

PLS HELP

asked
User Jan Tajovsky
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7.8k points

1 Answer

3 votes

Answer: y = (1/3)*x - 5

Step-by-step explanation: Hope this helps!

answered
User AndrewJM
by
8.0k points
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