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Question 1 (1 point)
Chan is throwing a ball from the ground at an initial velocity of 22.1 meters per seconds. He threw the ball so high that on it's way down it
got stuck in a tree 10 meters high. How long was the ball in the air before it got stuck in the tree?

asked
User Kafran
by
8.4k points

1 Answer

1 vote

9514 1404 393

Answer:

4.0 seconds

Explanation:

The equation for ballistic motion is ...

y = -4.9t^2 +22.1t

We want to find the larger value of t that makes y = 10.

10 = -4.9t^2 +22.1t

4.9t^2 -22.1t +10 = 0

Using the quadratic formula, we have ...

t = (22.1 + √(22.1² -4(4.9)(10)))/(2·4.9) = (22.1 +√292.41)/9.8 = 39.2/9.8

t = 4

The ball was in the air 4 seconds before it got stuck.

answered
User Derek Brown
by
8.8k points
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