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4(cos⁶A-sin6A) = cos³2A+3cos2A​

4(cos⁶A-sin6A) = cos³2A+3cos2A​
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4(cos⁶A-sin6A) = cos³2A+3cos2A​

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User Giuseppe
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1 Answer

11 votes

Answer:

On Paper

Explanation:

On the Paper

I hope this helped!

4(cos⁶A-sin6A) = cos³2A+3cos2A​-example-1
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User Craig Hannon
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