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Given: a//b c//d e//f, m<7=24, and m<20 = 80 what is m<1

Given: a//b c//d e//f, m<7=24, and m<20 = 80 what is m<1
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Given: a//b c//d e//f, m<7=24, and m<20 = 80 what is m<1

Given: a//b c//d e//f, m<7=24, and m<20 = 80 what is m<1-example-1
asked
User Martin Koles
by
8.0k points

1 Answer

6 votes

Answer:

m∠1 = 100

Explanation:

m∠2 = 80

m∠1 = 180 - 80 = 100

answered
User Daemes
by
8.1k points
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