Question

Pb(SO4)2 + 4 LiNO3 → Pb(NO3)4 + 2 Li2SO4

If 2.25 moles of lead (II) sulfate are combined with 9.62 moles of lithium nitrate, how moles of lithium sulfate can be created? please help

Answer 1

4.5 moles of lithium sulfate are produced.

Step-by-step explanation:

Given data:

Number of moles of lead sulfate = 2.25 mol

Number of moles of lithium nitrate = 9.62 mol

Number of moles of lithium sulfate = ?

Solution:

Chemical equation:

Pb(SO₄)₂ + 4LiNO₃ → Pb(NO₃)₄ + 2Li₂SO₄

Now we will compare the moles of lithium sulfate with lead sulfate and lithium nitrate.

Pb(SO₄)₂ : Li₂SO₄

1 : 2

2.25 : 2/1×2.25 = 4.5 mol

LiNO₃ : Li₂SO₄

4 : 2

9.62 : 2/4×9.62 = 4.81 mol

Pb(SO₄)₂ produces less number of moles of Li₂SO₄ thus it will act as limiting reactant and limit the yield of Li₂SO₄.