Question

Find the value of a' and 'b' if 2/ 7+3√5 =a-b√5​

Answer 1

Explanation:

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Answer 2

`a=(7)/(2) \ \ ,\ \ \ b=(3)/(2)`

Explanation:

`(2)/(7+3√(5) ) =(2* \left( 7-3√(5) \right) )/(\left( 7+3√(5) \right) \left( 7-3√(5) \right) )`

`=(2* \left( 7-3√(5) \right) )/(7^(2)-\left( 3√(5) \right)^2 )`

`=(2* \left( 7-3√(5) \right) )/(49-45 )`

`=(2* \left( 7-3√(5) \right) )/(4 )`

`=(7-3√(5) )/(2 )`

`=(7)/(2) -(3)/(2) √(5)`

Then

a = 7/2

b = 3/2