500 nm light passes through a circular aperture that has a diameter d = 30.0 Î¼m. A diffraction pattern forms on a screen 350 mm from the aperture. Calculate the area of the cen…

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asked Apr 8, 2021 56.8k views

1 Answer

Havvg · Answer 1 · 2021-04-14T07:48:05+0000

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Answer:

The value is
$A = 0.00214 \ m^2$

Step-by-step explanation:

From the question we are told that

The wavelength is
$\lambda = 500 \ nm = 500 *10^(-9) \ m$

The diameter of the aperture is
$d = 30 \mu m = 30*10^(-6) \ m$

The distance of the screen from the aperture is
$D = 350 \ m m = 0.350 \ m$

Generally the distance from the center the the edge of the central bright fringe is magmatically reparented as

$y = (m * \lambda * D)/(d)$

Generally m = 1 because after the central bright fringe we have the first order fringe

So

y = (1 * 500 *10^(-9) * 0.350)/(30*10^(-6))

=>
$y =0.00583 \ m$

Generally the area of the central bright fringe

$A = 2 \pi * y^2$

=>
A = 2 * 3.142 * 0.00583^2

=>
$A = 0.00214 \ m^2$