Question

What is the range of the function y=3√x+8?
0-∞ 0-8 O 0≤y<∞
O 2≤y<∞

Answer 1

Answer:
`y \geq 8`

Explanation:

The range of
`y=√(x)` is
`y \geq 0`

Multiplying this by 3, we get the range of
`y=3√(x)` is still
`y \geq 0`

Adding 8 to this, we get the range of
`y=3√(x)+8` is
`y \geq 8`.