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The function f(t)=290(0.91)^{t}f(t)=290(0.91) t represents the change in a quantity over t months. What does the constant 0.91 reveal about the rate of change of the quantity?

If you don't know the answer pls don't make up fake ones

The function f(t)=290(0.91)^{t}f(t)=290(0.91) t represents the change in a quantity-example-1
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User Rafee
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1 Answer

5 votes

Answer:

The function is decaying exponentially at a rate of 9% every month.

Step-by-step explanation: there you go bro

answered
User Marcelo Vismari
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