Question

5) A present falls out of Santa's sleigh and falls 2,500 meters to Earth. A) How much time did it fall

through the air? B) What is its final velocity?

Answer 1

(a) The time of fall is 22.59 s

(b) The final velocity of the present before it hits the ground is 221.38 m/s

Step-by-step explanation:

Given;

height of fall, h = 2500 m

(A) The time of fall is given as;

`t = \sqrt{(2h)/(g) }\\\\t = \sqrt{(2 \ * \ 2500)/(9.8) }\\\\t = \sqrt{(2 \ * \ 2500)/(9.8) }\\\\t = 22.59 \ s`

(B) The final velocity of the present before it hits the ground is given as;

v = u + gt

where;

u is the initial of fall = 0

v = 0 + (9.8 x 22.59)

v = 221.38 m/s